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Chord Harmonics (Posted on 2005-01-11) Difficulty: 3 of 5
Four chords of a circle are arranged in such a way that they form a quadrilateral shape, the length of the chords are as follows.

6cm, 7cm, 8cm and 9cm.

what is the area of the circle that will intersect all of the points?

No Solution Yet Submitted by Juggler    
Rating: 4.0000 (3 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re: Solution (some cheating) | Comment 2 of 9 |
(In reply to Solution (some cheating) by Jer)

I don't have a proof yet, but I get that R = 5.363825 so the area is 90.385564.

But at the same time I usually thoroughly confuse myself in these problems.  Your R is almost half of mine.  I wonder if I got confused between a diameter and a radius.  Argh.

More to come, I think.


  Posted by nikki on 2005-01-11 21:08:10
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