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Fibonacci Fractions (Posted on 2005-03-09) Difficulty: 3 of 5
What is the sum of 0.1+ 0.01+ 0.002+ 0.0003+ 0.00005+ 0.000008+ ..., where each term is the n-th Fibonacci number, shifted n places to the right (that is, divided by 10^n)?

See The Solution Submitted by e.g.    
Rating: 3.0000 (2 votes)

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re: What I found | Comment 5 of 17 |
(In reply to What I found by Hugo)

Solving Hugo's results algebraicly, the sum = 10/89

An odd coincidence, but I don't see the importance beyond this...


  Posted by Bryan on 2005-03-09 20:01:31
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