What is the sum of 0.1+ 0.01+ 0.002+ 0.0003+ 0.00005+ 0.000008+ ..., where each term is the n-th Fibonacci number, shifted n places to the right (that is, divided by 10^n)?
(In reply to
What I found by Hugo)
Solving Hugo's results algebraicly, the sum = 10/89
An odd coincidence, but I don't see the importance beyond this...
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Posted by Bryan
on 2005-03-09 20:01:31 |