Evaluate this sum in terms of n (the number of terms):
1 2 4 8 16
S = --- + ----- + ----- + ------- + ---------- + .....
2 5 41 3,281 21,523,361
(In reply to
Progress? by dopey915)
Where n is the number of terms, the denominator is the average of the first 2^n powers of 3 divided by the average of the first 2^(n-1) powers of 3.
D(1) = ((3^0 + 3^1)/2) / 3^0 = 2
D(2) = ((3^0 + 3^1 + 3^2 + 3^3)/4) / ((3^0 +3^1)/2) = 5
D(3) = ((3^0 + 3^1 + 3^2 + 3^3 + 3^4 + 3^5 + 3^6 + 3^7)/8) / ((3^0 + 3^1 + 3^2 + 3^3)/4) = 41
etc.
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Posted by MindRod
on 2005-12-22 10:35:51 |
re: Progress?
