1. If the number is odd, multiply it by three and add one.
2. If it is even divide it by two.
2a. If the result is still even, continue to divide by two until the result is odd.
3. Continue steps 1 and 2 until you get the same number twice.

[For example starting with 9 -> 28 -> 14 -> 7 which is considered one iteration. The next iteration brings this to 11.]

What number(s) does this process terminate at?
What starting value less than 200 takes the most iterations to terminate?

The process terminates at 4->2->1->4...

This is an unsolved problem in mathematics to show that for all numbers the process will terminate.

For the values less than 200 that take many steps, a brute force computer program would be the answer.