log
y(x) + log
x(y) = 43
What are the values of x and y?
(In reply to
re(2): Strange by levik)
Well this is how it goes -
We will notice that the reciprocal of log x y is log y x.
Therefore if log x y = A then log y x = 1/A
Then A + 1/A = 43
We solve the equation and find A
Afterwards we can find a simultaneous equation.
Through this we can find how much x and y are.
The answers are endless The most simple being (1,1) and (0,0)