Consider laying out 10 sets of 4 cards plus a turn-up, from a single deck of cards, forming what might appear to be 10 cribbage hands including a different turn-up for each. (Two cards will be left over.)
How could these sets be arranged to maximize the sum of the scores of these hands?
http://en.wikipedia.org/wiki/Cribbage may provide you with some guidance.
Note: Each hand has its own turn-card so a single jack in each hand could be the right jack.
(In reply to
re: Did I just peg out? by Steve Herman)
Thank you Steve. Correction made to post.
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Posted by Dej Mar
on 2006-07-18 20:58:48 |
re(2): Did I just peg out?
