perplexus.info :: Just Math : e, i, and π

e, i, and π (Posted on 2004-03-02)

i² = -1
e^(i π) = -1

(-e)^(i π) = ?

Simplify to a number without i. Leave e and π in their symbol forms.

See The Solution Submitted by Tristan

Rating: 2.8571 (7 votes)

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Solution

| Comment 11 of 12 |

(-e)^iπ=e^iπ*(-1)^iπ=(-1)*e^((iπ)*(iπ))=(-1)*e^(-π²)

Edited on August 20, 2007, 1:18 am

Posted by Praneeth on 2007-08-20 01:17:33

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