perplexus.info :: Just Math : Rounding the Root

Rounding the Root (Posted on 2008-03-03)

Some notation:

[x] = truncated x

<x> = rounded x = [x + 0.5]

E.g., <1.7> = 2, [1.7] = 1

Show:

<sqrt(n)> = [sqrt(n + [sqrt(n)])]

for natural number n.

See The Solution Submitted by FrankM

Rating: 4.0000 (3 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)

Kudos

Comment 1 of 1

Very interesting problem, nice solution, and a surprising result. Thanks!

Posted by Steve Herman on 2008-03-04 15:16:43

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