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Just Math
Rounding the Root (
Posted on 2008-03-03
)
Some notation
:
[x] = truncated x
<x> = rounded x = [x + 0.5]
E.g., <1.7> = 2, [1.7] = 1
Show
:
<sqrt(n)> = [sqrt(n + [sqrt(n)])]
for natural number n.
See The Solution
Submitted by
FrankM
Rating:
4.0000
(3 votes)
Comments: (
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)
Subject
Author
Date
Kudos
Steve Herman
2008-03-04 15:16:43
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