Solve the following set of equations for positive integers a and b:

1919(a)(b) mod 5107 = 1
1919(a+1)(b-1) mod 5108 = 5047
1919(a+2)(b-2) mod 5109 = 1148
1919(a+3)(b-3) mod 5110 = 3631
1919(a+4)(b-4) mod 5111 = 2280

(In reply to Solution by K Sengupta)

KS, I have:

(a+5107)(b-5107) = 26086391 (mod L)

which leads to only one solution.

Can you check your signs?

 

 

 

Posted by pcbouhid on 2008-07-31 17:12:43