Solve the following set of equations for positive integers a and b:

1919(a)(b) mod 5107 = 1
1919(a+1)(b-1) mod 5108 = 5047
1919(a+2)(b-2) mod 5109 = 1148
1919(a+3)(b-3) mod 5110 = 3631
1919(a+4)(b-4) mod 5111 = 2280

(In reply to re(2): Solution ------ can you check? by K Sengupta)

KS, you wrote:

(a-5107)(b+5107) (mod L) = -26086391

I have the same equation, but with the rhs positive!!

 

Posted by pcbouhid on 2008-08-01 13:05:37