When written as a decimal, the fraction m/n (with m < n, both positive integers) contains the consecutive digits 2, 5, 1 (in this order). Find the smallest possible n.

113/450 contains these digits consecutively, but whether this is the minimum n is another matter entirely. I rather doubt it but it serves as an upper bound for now.

Posted by Paul on 2009-01-05 15:10:46