Three positive integers P, Q and R, with P < Q < R, are in arithmetic sequence satisfying :
N*P*Q*R + Q2 = R2 - P2, where N is a positive integer.
Determine all possible quadruplet(s) (P, Q, R, N) that satisfy the above equation, and prove that no other quadruplet satisfies the given conditions.
1. N*P*Q*R + Q^2 = R^2 - P^2:
I Let Q=p;Let P=(p-k); Let R=(p+k)
II n*p*(p-k)*(p+k)+p^2=(p+k)^2-(p-k)^2
III np^3+p^2-k^2np = 4kp Expanding, simplifying
IV p(np+1) = k(kn+4) Cancelling p throughout
When {k,n,p} = {2,1,3}
2. Solving for successive n reveals that {k}={-6/n, 2/n}, {p}={-4/n,3/n}, so {k,n,p} = {2,1,3} is unique in the positive integers.
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Posted by broll
on 2011-07-04 02:08:01 |