All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math > Calculus
Maximum Value (Posted on 2002-06-19) Difficulty: 3 of 5
We have :
      x^2+xy+y^2=3 and
      y^2+yz+z^2=16
      A=xy+yz+zx
Find the maximum value of A. Find x, y and z when A=max value.

(Remember the category)

See The Solution Submitted by vohonam    
Rating: 3.2857 (7 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Hints/Tips re: Methods to solve this | Comment 8 of 19 |
(In reply to Methods to solve this by vohonam)

We use 2 inequalities :
1)Cauchy's inequality :
a + b >= 2*square root of (a*b) ; (a,b>0)
or a common Chauchy's inequality :
((a1+a2+a3+.....+a(n))/n)^n >= a1*a2*...*a(n)
"=" when a1=a2=...=a(n)
2)Chebyshev's inequality :
absolute value of (a*x+b*y) <= square root of ((a^2+b^2)*(x^2+y^2))
"=" when a/x=b/y
Those inequalities are easy to prove.
From these, I hope that you can solve this problem
  Posted by vohonam on 2002-06-19 17:28:58

Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (3)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information