Determine all possible pairs (x,y) of
half-integers, with x ≤ y, that satisfy this equation:
[x
2] + [y
2] = 2016
Prove that there are no others.
*** [x] denotes the greatest integer ≤ x.
(In reply to
re: computer solution by broll)
Of the 16 WolframAlpha solutions, only half have x <= y. The only two that my list failed to include were two cases where both x and y were negative:
x=-85/2, y=-29/2
x=-71/2, y=-55/2
So there are actually 8 solutions.
|
Posted by Charlie
on 2013-08-01 09:41:59 |