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Forcing a Polynomial Factor (Posted on 2013-08-03) Difficulty: 3 of 5
Find the values for a and b to force the polynomial x10 + ax5 + b to have x2+2x+3 as a factor.

See The Solution Submitted by Brian Smith    
Rating: 4.0000 (1 votes)

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Another approach | Comment 2 of 4 |
If you don't like dealing with imaginary numbers, another approach is to just divide x2+2x+3 into x10 + ax5 + b.  I haven't actually done it, but you will wind up with a remainder in the form of 
(e + af)*x + (g + ah + b).

Set each of these equal to 0, giving a = -e/f and b = -g +he/f




  Posted by Steve Herman on 2013-08-04 15:34:09
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