I have in mind 4 positive numbers, which I would like you to find.
Out of the set of 6 pair-wise products of those numbers I am going to omit one.
The remaining five are: 8,10,12,24,30.
(In reply to
re(2): Solution with Analysis by Steve Herman)
I like your expansion of
the solutions’ set.
Following your idea, this problem has 4 solutions. One
uses integers only.
The other 3, including yours:
SH: (2*sqrt(5/3),
4*sqrt(3/5), 5*sqrt(3/5), 6*sqrt(5/3))
AT: (2*sqrt(15/4),
4*sqrt(15/4), 5*sqrt(4/15), 6*sqrt(4/15))
AT: (2*sqrt(12/5),
4*sqrt(5/12), 5*sqrt(12/5), 6*sqrt(5/12))
Feel free to check/comment.
re(3): Solution with Analysis
