Determine the total number of values of a positive integer N having at most four digits such that:

(i) The digit 1 occurs an odd number of times in N, and:

(ii) Each of the digits 2, 0 and 6 occurs an even number of times in N. (An even number includes zero), and:

(iii ) Any of the remaining six digits may or may not occur in N.

(In reply to My answers (with and without leading zeros) by Ady TZIDON)

The puzzle asks that each of 2, 0, and6 occurs an even number of times.  "each"  implies individually rather than as a group.  It looks as if you consider say 62 as an even set while I consider it two odd occurrences of individual digits. 

Posted by Charlie on 2016-04-05 13:33:52