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Polynomial of degree 3n (Posted on 2016-05-07) Difficulty: 3 of 5
A polynomial P(x) of degree 3n has the value 2 at x= 0, 3, 6,..., 3n, and:
the value 1 at x= 1, 4, 7, ... , 3n-2, and:
the value 0 at x= 2, 5, 8, ... , 3n-1.

Given that P(3n+1) = 730, find n.

No Solution Yet Submitted by K Sengupta    
Rating: 4.0000 (2 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re(2): possible solution | Comment 3 of 6 |
(In reply to re: possible solution by ken)

Thanks, Ken.


Boy, was I wrong!  For any n, the problem specifies 3n + 2 values, so not all n's will work.  I "solved" the problem where the polynomial has the value 2 at x = 0, 3, 6, ... 3n - 3.

  Posted by Steve Herman on 2016-05-08 08:36:46
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