perplexus.info :: Calculus : Maximum Value

Maximum Value (Posted on 2002-06-19)

We have :

      x^2+xy+y^2=3 and
      y^2+yz+z^2=16
      A=xy+yz+zx

Find the maximum value of A. Find x, y and z when A=max value.

(Remember the category)

See The Solution Submitted by vohonam

Rating: 3.2857 (7 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)

No Subject

| Comment 10 of 19 |

x=1, y=1, z=(-1+SQRT(61))/2 A=SQRT(61)
x=-1, y=-1 z=(1-SQRT(61))/2 A=SQRT(61)

Posted by lucky on 2002-06-23 07:48:58

Please log in:

Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (3)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:


perplexus dot info