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Red vs Black Cuts (Posted on 2017-06-05) Difficulty: 3 of 5
A deck of 52 cards is shuffled and cut into two halves of 26 cards each. What is the probability that the number of red cards (hearts and diamonds) in the first half is equal to the number black cards (clubs and spades) in the second half?

Two jokers are added to the deck. The deck of 54 cards is shuffled and cut into two halves of 27 cards each. Now what is the probability that the number of red cards in the first half is equal to the number black cards in the second half?

See The Solution Submitted by Brian Smith    
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re: solution | Comment 4 of 8 |
(In reply to solution by Daniel)

I did find a problem in my calculation, I forgot to account for the choice of which joker ends up in the first half, thus there are 2*52C26 ways of getting the desired result and thus the answer is now 676/1431 or approximately 47.24%



  Posted by Daniel on 2017-06-05 09:40:27
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