Three bets were made:
(1) First, A won from B as much as A had originally.
(2) Second, B won from C as much as B then had left.
(3) Finally, C won from A as much as C then had left.
The three players ended up with equal amounts of money.
Who began with 50 cents?
A started with amount a.
B started with amount b.
C started with amount c.
A B C
After 1st bet: 2*a b-a c
After 2nd bet: 2*a 2*(b-a) c+a-b
After 3rd bet: a-c+b 2*(b-a) 2*(c+a-b)
a-c+b = 2*b - 2*a
3*a - b = c (i)
a-c+b = 2*c+2*a-2*b
3*b - a = 3*c (ii)
6*b - 10*a = 0 (ii) - 3 * (i)
3*b = 5*a
b a c
5 3 4
10 6 8
15 9 12
20 12 16
...
50 30 40
B started with 50 cents, as 50 is not divisible by 3 or by 4.
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Posted by Charlie
on 2017-09-06 13:13:58 |