perplexus.info :: Just Math : Sine recurrence

Sine recurrence (Posted on 2019-01-08)

If a₀ = sin² (π/45) and a_n+1 = 4a_n(1 - a_n) for n >= 0, find the smallest positive integer n such that a_n = a₀

No Solution Yet Submitted by Danish Ahmed Khan

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re(2): @ DAK

| Comment 3 of 6 |

(In reply to re: @ DAK by Charlie)

CHarlie

I assumed it is Pi, however wanted to be sure.

TNX.

Posted by Ady TZIDON on 2019-01-08 10:06:31

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