A circumference was divided in n equal parts. On each of these parts one number from 1 to n was placed such that the distance between consecutive numbers is always the same. Numbers 11, 4 and 17 were in consecutive positions. In how many parts was the circumference divided?
I wrote a long explanation but it got deleted.
Short version: n=20 and the numbers are as follows.
11,4,17,10,3,16,9,2,15,8,1,14,7,20,13,6,19,12,5,18
Every third space was consecutively numbered.
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Posted by Jer
on 2020-12-21 10:08:30 |
Solution
