42x = 2-x
4^(2^x) = 2^(-x) (2^x)*ln4 = -x*ln2 2^(x+1)*ln2 = -x*ln2 2^(x+1) = -x (x+1)*ln2 = ln(-x), which if there is to be a defined solution leads to rhs à x<0, LHS à x >= -1<p><p>
By inspection, x=-1 is the only solution
Edited on October 24, 2023, 5:05 pm
blackjack
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flooble's webmaster puzzle
Alternate method
