Define:
d/dx(f(x)) = f'(x)
where f'(x) = gradient (or slope) of f(x) at x = x.
Prove that:
d/dx(x^2) = 2x
without using calculus.
(In reply to
re: Hmmmm by TomM)
the question is, if you had to determine the gradient of y = x^2 at any point, back in say 1000 A.D. how would you do it? that is how i came up with this when learning calculus..
in the version you suggest youre basically removing half of the
problem, plus, in my opinion, making it much less appealing and
interesting to solve. the fact that its "calculus without calculus"
is what i think makes it cool. (thats why i chose "No Calculus" name)