Two people (A and B) want to meet each other to have lunch, and plan to meet at B's house party. A starts out for B's house, but when A is a mile away from B's house, B realizes that his house is a mess and A's isn't. So B takes off to meet A.

Once they meet, they talk for a while, and decide to meet at A's house instead. A goes back to her house to wait for B, and B goes to his house to pick up his food, then goes to A's house. They arrive at A's house at exactly the same time. If B walks twice as fast as A, how far apart do the two people live?

being a mile away from B's, they both start back to thier respective houses at the same time. everyone else thinks A waits until B gets back to his house to start towards his house. let's say A's house is west and B's house is east.

B walks east 1 mile to get back to his house.While that is happening, A walked half a mile to the west. then B walked back west to the meeting place (a mile away) in the time it took A to go another half-mile west. seperated by a mile now, just continue halving the distance between the two and adding it together until you come to the point where they meet.

answer:A's house is 3 miles away from B's house.

Posted by ben on 2003-10-29 22:53:02