Let f(x) = √(1-x²)
Find the definite integral
of f(x) between x = 0 and x = 1
You don't even need calculus for this one.
The function is a circle centered at the origin with r=1.
The integral asks for the area of the upper right quarter of the circle.
This area is pi/4.
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Posted by Jim Lyon
on 2002-08-06 06:16:05 |