Let f(x) = √(1-x²)
Find the definite integral
of f(x) between x = 0 and x = 1
(In reply to
Easy solution by Jim Lyon)
Wait... Assuming it's a circle, wouldn't the integral from 0 to 1 be the area of HALF of the circle? Both the right-hand quadrants of a circle centered on the origin would be in the positive X region.
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Posted by levik
on 2002-08-06 06:43:58 |