Let f(x) = √(1-x²)
Find the definite integral
of f(x) between x = 0 and x = 1
(In reply to
re: Easy solution by levik)
The function describes the upper half of the circle, for -1 <= x <= 1. (It would describe the whole circle if there were a plus-or-minus in front of the square root.)
The integral asks for the right half of that. Hence, pi / 4.
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Posted by Jim Lyon
on 2002-08-07 10:48:55 |