Let f(x) = √(1-x²)
Find the definite integral
of f(x) between x = 0 and x = 1
(In reply to
re(2): Easy solution by Jim Lyon)
You correctly stated that f(x) is the upper half of the circle, but when you said that if there were a ± before the radical, the "function" would descibe the whole circle, you were not quite correct. the relation would describe the whole circle, but it would no longer be a function. A function y = f(x) can have only one value y for any one value of x.
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Posted by TomM
on 2002-08-07 18:49:40 |
re(3): Easy solution
