Let f(x) = √(1-x²)
Find the definite integral
of f(x) between x = 0 and x = 1
(In reply to
re(4): Easy solution by levik)
This is a typical misconception.. The square root of a number is always a positive number. This must not be confused with the following valid reasoning
x² = 1 implies that x = ±√1
but √1 = 1. (ie √ is a function as TomM said)