Using the digits in 1996 and any operations (but not mathematical constants), try to write equations that have the numbers from 0 to 100 as the answer.
For example with 1995:
0 = 1*(9-9)*5
2 = (19-9)/5
etc.
Provide as many as you can. Digits 1,9,9 and 6 do not have to appear in order. (But each digit has to be used - 1 and 6 once, 9 twice.)
This is more of a game than a puzzle
Okay, I've managed to find equations for lots of the numbers, but I currently have 14 outstanding. They are:
29 to 33, 40 to 42, 47, 49, 67, 71, 89 and 91
I've got all the rest...
Quite a few in the thirties and forties missing, as you can see... :-/ Hmmmm...
Missing numbers
