A number of 50 digits has all its digits equal to 1 except the 26th digit. If the number is divisible by 13, then find the digit in the 26th place.
(In reply to
re(4): a little more straightforward by Richard)
I wrote
If you call the leftmost digit (most significant) the first digit then the 26th digit moves left one place, giving instead
111111 111111 111111 111111 1x 111111 111111 111111 111111
but the digit moves right, not left, of course. Sorry for the misteak.
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Posted by Richard
on 2003-11-19 21:30:45 |
re(5): a little more straightforward
