A number of 50 digits has all its digits equal to 1 except the 26th digit. If the number is divisible by 13, then find the digit in the 26th place.
(In reply to
re(5): a little more straightforward by Richard)
Wait, your right. I guess I was thinking about it all wrong. Without thinking, I must have tried to find a digit where the big number is 13^ a certain integer. I was confusing myself.
|
|
Posted by Tristan
on 2003-11-20 19:31:37 |
re(6): a little more straightforward
