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Complex Number Query (Posted on 2016-04-03) Difficulty: 3 of 5
Determine all possible values of a complex number z such that:
(3z+1)(4z+1)(6z+1)(12z+1) = 2

  Submitted by K Sengupta    
Rating: 5.0000 (1 votes)
Solution: (Hide)
The four roots of the given equation are:
Z= (-5 +/- i*sqrt(23)/24 OR (-5 +/- sqrt(33)/24.

For an explanation refer to the solution submitted by Brian Smith in this location..

Comments: ( You must be logged in to post comments.)
  Subject Author Date
SolutionSolution (An easier way)Brian Smith2022-05-27 09:56:20
SolutionSolution (probably the hard way)Jer2016-04-03 20:19:34
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