38s and Bunches of 1s (Posted on 2017-06-30)

	Submitted by Brian Smith
Rating: 4.5000 (2 votes)
Solution:	(Hide)
Let S(x) denote the member of the sequence with x 1s. (x starts at 0) If x mod 3 = 1 then S(x) is a multiple of 3. If x mod 3 = 2 then S(x) is a multiple of 37. If x mod 3 = 0 then S(x) is a multiple of 2333...3 where the number of 3s is equal to x. More details can be found in the comments.

	Subject	Author	Date
	Puzzle Solution (Proof)	K Sengupta	2022-07-28 08:15:54
	Proof	Math Man	2017-07-01 21:38:12
	re: Another way of seeing part of it	broll	2017-06-30 23:14:23
	Another way of seeing part of it	Jer	2017-06-30 14:03:47
	Nice problem	broll	2017-06-30 10:38:00
	re(2): No proof but a pattern found	Charlie	2017-06-30 10:14:56
	re: No proof but a pattern found	chun	2017-06-30 09:42:22
	No proof but a pattern found	Charlie	2017-06-30 09:04:10