perplexus.info :: Just Math : Log Value Extrication

Log Value Extrication (Posted on 2023-01-22)

Each of M and N is a positive real number that satisfies the following simultaneous equations:

log₁₄(7) = M
14^N = 5

Determine the value of log₃₅(28) in terms of M and N.

Submitted by K Sengupta

Rating: 4.0000 (1 votes)

Solution: (Hide)

log₁₄(28)
= log₁₄(14²/7)
= 2 - log₁₄(7)
= 2 - M
log₁₄(35)
= log ₁₄7+log ₁₄5
= M+N
So, log ₃₅28 2-M =------ M+N
For an alternate method, refer to the solution submitted by Larry in this location.

Comments: ( You must be logged in to post comments.)

Subject	Author	Date
solution	Charlie	2023-01-22 11:02:41
Solution	Larry	2023-01-22 09:44:38

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