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e pluribus unum ii (Posted on 2004-01-22) Difficulty: 3 of 5
Below are three groups of three numbers each. Combine the numbers in each group using the standard binary operations (addition, subtraction, multiplication, division, and exponentiation) so that each group yields the same number.
  1. 3, 15, 18
  2. 10, 13, 36
  3. 24, 27, 39

For an example, see the first problem.

  Submitted by DJ    
Rating: 4.7143 (7 votes)
Solution: (Hide)
18 - (15 ÷  3) = 13
36 -  10 - 13  = 13
39 ÷ (27 - 24) = 13

Comments: ( You must be logged in to post comments.)
  Subject Author Date
Puzzle AnswerK Sengupta2023-09-26 23:47:44
No SubjectDrBob2004-01-29 16:48:00
re(2): DJ U BAD BOYAdy TZIDON2004-01-22 17:34:06
re: solution :-) -- There's also... (variations)Charlie2004-01-22 14:37:37
re: DJ U BAD BOYSilverKnight2004-01-22 14:00:29
DJ U BAD BOYAdy TZIDON2004-01-22 13:50:58
Solutionsolution :-)SilverKnight2004-01-22 13:42:05
Hints/Tipsre(2): an error in your DATADJ2004-01-22 13:29:35
re: an error in your DATACharlie2004-01-22 13:19:05
Hints/Tipsan error in your DATAAdy TZIDON2004-01-22 12:12:32
re: Attempt at a computer solution -- resultsSam2004-01-22 11:40:17
Some Thoughtsre: Attempt at a computer solution -- resultsCharlie2004-01-22 11:32:29
Some ThoughtsAttempt at a computer solutionCharlie2004-01-22 11:21:33
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