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 e pluribus unum (Posted on 2003-12-08)
Below are three groups of three numbers each. Combine the numbers in each group using the standard binary operations (addition, subtraction, multiplication, division, and exponentiation) so that each group yields the same number (there is one unique solution).
1. 1, 6, 11
2. 13, 20, 33
3. 20, 33, 40
```For example, given:
15, 19, 24          11, 30, 36          20, 22, 36
you could make:
24÷(19-15)=6       (30+36)÷11=6         20+22-36=6```

 See The Solution Submitted by DJ Rating: 3.8462 (13 votes)

 Subject Author Date More than one solution... Dej Mar 2012-09-23 06:42:17 Solution Praneeth Yalavarthi 2007-07-17 12:59:13 Solution K Sengupta 2007-03-16 10:56:49 agreeing about solution Emily 2005-08-26 21:39:19 Don't start that again Minion123 2003-12-09 01:29:00 Please don't: Gamer 2003-12-08 22:04:09 a wild stab ken 2003-12-08 21:56:15 re: This one was really hard.... Victor Zapana 2003-12-08 20:58:51 This one was really hard.... Penny 2003-12-08 18:54:31 Solution ethan 2003-12-08 16:38:47 Solution (No computer program used) Penny 2003-12-08 16:22:14

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