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 e pluribus unum (Posted on 2003-12-08)
Below are three groups of three numbers each. Combine the numbers in each group using the standard binary operations (addition, subtraction, multiplication, division, and exponentiation) so that each group yields the same number (there is one unique solution).
1. 1, 6, 11
2. 13, 20, 33
3. 20, 33, 40
```For example, given:
15, 19, 24          11, 30, 36          20, 22, 36
you could make:
24÷(19-15)=6       (30+36)÷11=6         20+22-36=6```

 See The Solution Submitted by DJ Rating: 3.8462 (13 votes)

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 agreeing about solution | Comment 8 of 11 |
I liked this one...
this is the solution I got (obviously, since it works,
it is right!:)

1 times 6 times 11 equals 66
13 plus 33 plus 20 equals 66
(33 times 40) diveded by 20 equals 66.

I know someone already posted the solution, but I wanted
to, too!
 Posted by Emily on 2005-08-26 21:39:19

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