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e pluribus unum (Posted on 2003-12-08) Difficulty: 3 of 5
Below are three groups of three numbers each. Combine the numbers in each group using the standard binary operations (addition, subtraction, multiplication, division, and exponentiation) so that each group yields the same number (there is one unique solution).
  1. 1, 6, 11
  2. 13, 20, 33
  3. 20, 33, 40
For example, given:
15, 19, 24          11, 30, 36          20, 22, 36
you could make:
24(19-15)=6       (30+36)11=6         20+22-36=6

See The Solution Submitted by DJ    
Rating: 3.8462 (13 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution Solution | Comment 9 of 11 |

1   6 11
= 13 + 20 + 33
= 33 40 20
= 66


  Posted by K Sengupta on 2007-03-16 10:56:49
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