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Exponentiate In Pairs, Get Numbers (Posted on 2007-06-08) Difficulty: 2 of 5
Determine all possible positive real triplets (a, b, c) satisfying ab =c; bc = a and ca = b

  Submitted by K Sengupta    
Rating: 4.0000 (1 votes)
Solution: (Hide)
When a =1, then: ab = c, gives b=c, while ca=b gives c= b. Thus, b=c=a, so that (a,b,c) =(1, 1, 1).

When a>1, we have c = ab> 1 and b = ca > 1. Now, c = ab > a; while a = bc > b, so that c> b. But, b= ca> c. This is a contradiction.

When a< 1, we have c, b < 1. Now, c = ab < a; while a = bc < b, so that c< b. But, b= ca< c. This is a contradiction.

Combining the three cases, (a,b,c) = (1,1,1) is the only possible solution to the given problem.

Comments: ( You must be logged in to post comments.)
  Subject Author Date
Another solutionGamer2007-06-08 23:53:55
re(3): Cyclicalbrianjn2007-06-08 21:14:52
re(2): CyclicalRobby Goetschalckx2007-06-08 09:54:37
re: Cyclicalbrianjn2007-06-08 09:35:25
Cyclicalbrianjn2007-06-08 09:32:59
SolutionProofOld Original Oskar!2007-06-08 09:31:56
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