perplexus.info :: Calculus : Eccentric Integral

Eccentric Integral (Posted on 2010-02-18)

The respective eccentricities of the hyperbola x²/ a² - y²/ b² = 1 and its conjugate y²/ b² - x²/ a² = 1 are denoted by e and f(e).

Evaluate:

√2
∫ (f(e) + f(f(e))) de
1

Submitted by K Sengupta

Rating: 5.0000 (1 votes)

Solution: (Hide)

3/2.
For an explanation, refer to the solution submitted by Daniel in this location.

Comments: ( You must be logged in to post comments.)

Subject	Author	Date
analytical solution	Daniel	2010-02-19 12:15:26
An attempt using numerical integration (spoiler?)	Charlie	2010-02-19 11:48:51

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