Home > Just Math
| Prime and Divisors Derivation (Posted on 2010-06-17) |
 |
Determine the maximum value of a prime number x ≤ 999, such that Y has precisely 42 distinct positive integer divisors (including 1 and Y), where:
Y = x(x+1)2.
|
|
Submitted by K Sengupta
|
|
Rating: 5.0000 (1 votes)
|
|
|
Solution:
|
(Hide)
|
The required maximum value of x is 823.
For a detailed explanation, refer to the solution submitted by Praneeth in this location.
|
Comments: (
You must be logged in to post comments.)
|
|
Please log in:
Forums (0)
Newest Problems
Random Problem
FAQ |
About This Site
Site Statistics
New Comments (3)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On
Chatterbox:
|
