perplexus.info :: Just Math : Sum Divisors

Sum Divisors - 1 = Number (Posted on 2010-12-16)

Determine all possible values of a positive integer P, such that P-1 has three divisors Q, R and S, with Q < R < S, such that: Q + R + S = P

Submitted by K Sengupta

Rating: 5.0000 (1 votes)

Solution: (Hide)

The solutions are P=13 = 3+4+6 and P=31 = 6+10+15
For an explanation, refer to the solution submitted by Jer in this location.

Comments: ( You must be logged in to post comments.)

Subject	Author	Date
Computer solution	Danish Ahmed Khan	2012-10-26 06:29:02
re: Solution	Steve Herman	2010-12-18 11:26:26
Solution	Jer	2010-12-17 16:26:14

Please log in:

Login:
Password:
Remember me:

Sign up! \| Forgot password

Search:

Search body:

Forums (1)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (6)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:


perplexus dot info