perplexus.info :: Just Math : Perfectly Harmonic

Perfectly Harmonic (Posted on 2013-11-13)

Each of the three positive integers (81+K), (162+K) and (337+K) is a perfect square such that their positive square-roots are in harmonic sequence.

Determine the value of K, and prove that no other value for K is possible.

Submitted by K Sengupta

Rating: 5.0000 (1 votes)

Solution: (Hide)

K = 63 is the only solution.

For a detailed explanation, refer to the solution submitted by Paul in this location.

Comments: ( You must be logged in to post comments.)

Subject	Author	Date
re(2): Solution	Ady TZIDON	2013-11-15 02:57:11
re: Solution	Math Man	2013-11-14 20:26:40
Solution	Paul	2013-11-13 19:58:55

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