perplexus.info :: Just Math : Divisible by 28

Divisible by 28 (Posted on 2014-12-21)

Each of a, b and c is a positive integer with a ≤ b ≤ c ≤ 70.

Find total number of triplets (a, b, c) such that a² + b² + c² is divisible by 28.

Submitted by K Sengupta

Rating: 5.0000 (1 votes)

Solution: (Hide)

There are 1035 sets of triplets (a,b,c) that meet the given conditions.
For an explanation, refer to:
(1) The analytical solution submitted by Ady TZIDON in this location.
(2)The computer program assisted solution submitted by Charlie in this location.

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