perplexus.info :: Just Math : From M to N

From M to N (Posted on 2023-05-22)

Prove the following theorem:
For any string of decimal digits, representing number M there is an integer n such that the number N=2^n begins with the string M.

Find a value of N for M=2023?

No Solution Yet Submitted by Ady TZIDON

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Subject	Author	Date
re: Other 4-digit M values -- continued	Charlie	2023-05-22 12:58:51
Other 4-digit M values	Charlie	2023-05-22 12:54:00
Part 2	Charlie	2023-05-22 12:40:34
Old-fogey logic	Steve Herman	2023-05-22 11:30:02

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