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From M to N (Posted on 2023-05-22) Difficulty: 3 of 5
Prove the following theorem:
For any string of decimal digits, representing number M there is an integer n such that the number N=2^n begins with the string M.

Find a value of N for M=2023?

No Solution Yet Submitted by Ady TZIDON    
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  Subject Author Date
re: Other 4-digit M values -- continuedCharlie2023-05-22 12:58:51
Other 4-digit M valuesCharlie2023-05-22 12:54:00
SolutionPart 2Charlie2023-05-22 12:40:34
Old-fogey logicSteve Herman2023-05-22 11:30:02
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