The five girls, named G1, G2,…G5 arranged the round-table sitting so that between each two of them there were at least two out of 12 boys , B1, B2,…B12.
In how many ways is such arrangement possible?
(In reply to
solution by Charlie)
I did not consider the possibility that less than 12 boys would be seated at the round table. If a smaller number can "play" then the number of possible ways is quite a bit more.
Also the problem states that between any two girls there are at least 2 boys, not just 1: I interpreted this to mean 2 boys between each adjacent pair of girls, since adjacent girls is a subset of any two girls.
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Posted by Larry
on 2023-10-02 20:16:19 |
re: solution
